IS THERE an IS keyword in C++ like in C#?

YES, there is an IS keyword in C++. Just like in C#.

WRONG
WRONG

A few days ago I had this question and I saw this answer “NO” and I took it and accepted it.

Only today I saw in some sample code just use of typeid(). And guess what? typeid() turns BLUE in the IDE!

#include <iostream>
#include <string>
using namespace std;

class Entity
{
public:
  int hp ;
};

class Grunt : public Entity
{
public:
  string name ;
};

int main()
{
  Grunt grom ;
  grom.hp = 500 ;
  grom.name = "GROM HELLSCREAM!" ;

  const type_info * typeOfG = &typeid( grom ) ;

  cout << typeOfG->name() << endl;

  Entity wisp ;
  wisp.hp = 120 ;

  const type_info * typeOfWisp = &typeid( wisp ) ;

  cout << typeOfWisp->name() << endl; 

  // equivalent of C# is:
  //if( grom is Grunt )
  //{
  //}

  // accomplished by
  string classGrunt = "class Grunt" ;
  if( typeid(grom).name() == classGrunt )
  {
    cout << "Grom is a grunt" << endl;
  }
  else
  {
    cout << "Grom is NOT a grunt" << endl;
  }

  // so we coudl make this a bit more elegant by
#define is( obj, type ) typeid(obj).name()==type
  if( is( grom, classGrunt ) )
  {
    cout << "Grom is a grunt" << endl;
  }
  else
  {
    cout << "Grom is NOT a grunt" << endl;
  }

  /*
  class type_info {
    bool operator==( type_info rhs ) ;
    bool operator!=( type_info rhs ) ;
    int before( type_info rhs ) ;
    const char* name();
    const char* raw_name();
  } ;
  */

}